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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 21:31:59 IST
Accepted Answer [?]
![[Up]](/templates/default/images/icon_up.gif "[Up]")
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k=1/(tan(A+B/2)tan(B-A/2)
= cos(A+B/2)cos(A-B/2)/sin(A+B/2)sin(B-A/2)
= 2cos(A+B/2)cos(A-B/2)/2sin(A+B/2)sin(B-A/2)
= cosA+cosB/cosA-cosB
= (m+1)/(m-1)
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this reply: 5 points
(with 1 
in 1 votes ) [?]
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