sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: fghgjh
Forum Index -> Integral Calculus -> View Full Question like the article? email it to a friend.  
Author Message
sboosy (3063)

Blazing goIITian

Olaaa!! Perrrfect answer. 539  [723 rates]

sboosy's Avatar

total posts: 510    
offline Offline
\int cosec^4x \,dx  \\ \\ = \int cosec^2x cosec^2x\,dx \\ \\ = \int (1+\cot^2x)cosec^2x\,dx \\ \\ = \int cosec^2x \,dx + \int \cot^2xcosec^2x\,dx \\ \\ = -\cot(x) - \frac{\cot^3x}{3}+c \\ \\ \\ \int \frac{\sin(2x)}{\sin(5x)\sin(3x)}\,dx \\ \\ = \int \frac{\sin(5x-3x)}{\sin(5x)\sin(3x)}\,dx \\ \\ = \int \cot(3x)\,dx - \int \cot(5x)\,dx \\ \\ = \frac{1}{3} \log(|\sin(3x)|) - \frac{1}{5} \log(|\sin(5x)|)+c
 this reply: 9 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya