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[Post New]16 Apr 2008 18:48:42 IST
    Subject: Re:see this
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sboosy (3063)

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Olaaa!! Perrrfect answer. 539  [723 rates]
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\mbox{If} \ x+3 \ \mbox{machines took} \ 12 \ \mbox{days,then} \\ \\ x+4 \ \mbox{machines would have taken} \ \frac{12(x+3)}{x+4} \ \mbox{(Inverse variation here..more machines ..less time)} \\ \\ \mbox{Now according to the wrong data} \ x \ \mbox{machines take} \ 10 \ \mbox{days} \\ \\ x+4 \ \mbox{machines would have taken} \ \frac{10x}{x+4} \ \mbox{days} \\ \\ \mbox{So difference between the actual and predicted will be} \\ \\ \frac{12(x+3)}{x+4} - \frac{10x}{x+4} = \frac{2x+36}{x+4}
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