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[Post New]16 Apr 2008 19:36:53 IST
    Subject: Re:Please solve it immediately!!!!!
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sboosy (3046)

Blazing goIITian

Olaaa!! Perrrfect answer. 536  [719 rates]
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2.) T_k = \frac{k(k+1)}{k!} \\ \\ \sum_{k=0}^{k=n}\frac{k(k+1)}{k!} \ = \sum_{k=0}^{k=n} (\frac{k^2}{k!}+\frac{k}{k!}) = \sum_{k=0}^{k=n} (\frac{k}{(k-1)!}+\frac{1}{(k-1)!}) \\ \\ = (\frac{1}{0!}+\frac{2}{1!}+\frac{3}{2!}+...)+(\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+....) \\ \\ \mbox{Splitting the first bracket into two we have} \\ \\ = (1+1+\frac{1}{2!}+\frac{1}{3!}+....)+(1+1+\frac{1}{2!}+\frac{1}{3!}+...)+(1+1+\frac{1}{2!}+\frac{1}{3!}+....) \\ \\ =3e
 this reply: 12 points  (with 2 Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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