|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2008 21:48:52 IST
|
|
|
EQUATION OF ANY TANGENT TO PARABOLA IS GIVEN BY y = mx + a/m EQUATION OF ANY TANGENT TO ABOVE PARABOLA IS GIVEN BY y = mx + 1/m............................1 now this is also a tangent to second parabola. so it should satisfy it put the value of y from 1 in the equation of second it will be quadratic in x then put D = 0 this will give the value of m
RATE ME
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|