case 1 : person who is both lawyer & accountant is selected , then any three from the rest 10 can be selected

 

so no .of ways = 10C3 = 120

 

case 2: the uniquely talented above person is not selected leaving three possibilites

i) 2 lawyers & 2 accountants are selected , no .of ways = 5C2 * 5C2 = 100

 

ii) (3 lawyers and 1 accountant) or (1 lawyer & 3 accountants) = 2*5C3*5C1 = 100

 

 

so total ways = 120 + 200 = 320