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Marshall Eriksen (1586)

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y^2 = x^2 - x^3
Differentiate wrt x
2y.dy/dx = 2x - 3x^2
dy/dx = [2x - 3x^2]/2y
= x (2 - 3x)/2 x^2 (1-x)
= (2-3x)/2x(1-x)

i think my answer is correct......if yes plzz rate me......if i have gone wrong...please tell me where

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