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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: PLEASE REPLY-
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[Post New]18 Apr 2008 19:39:27 IST
    Subject: Re:PLEASE REPLY-
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sweet08 (72)

Cool goIITian

Olaaa!! Perrrfect answer. 12  [18 rates]
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a+2b=tc
b+3c=sa
b=sa-3c  sub in 1st eq
=> a+2(sa-3c)=tc
  a-6c=-2sa+tc
 =>t=-6   sub in 1st eq
 a+2b=-6c
a+2b+6c=0
 
 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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