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1050=2.3.5.5.7
the answer is 1875.....
consider a,b,c,d,e as five boxes(x1,x2,x3,x4,x5)
2,3,7 can enter these boxes in 5*5*5 ways
5 can enter these boxes as two 5's or one 25
so no of ways = 5C1+5C2=15 ways
toatl no of ways = 5*5*5*15=1875 ways
so total no of solutions is 1875
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Moderation Team
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