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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Apr 2008 20:54:22 IST
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sin(x+y)=log(x+y) then sinxcosy+cosxsiny=log(x+y) then dy/dx(cosxcosy-sinxsiny)+(cosxcosy-sinxsiny)=1/x+y(1+dy/dx) ,then [cos(x+y)-1/x+y]dy/dx=1/x+y-cos(x+y) then dy/dx= -[1-cos(x+y)(x+y)/1-cos(x+y)(x+y)] then dy/dx= -1
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