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Priyesh (1601)

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Vineetvsb is correct

bcoz in the given condition x^y+1=z where x,y,z are primes

x has to be an even prime no. because if x is taken as odd the square(or raised to any power) of it will give a odd no. & by adding 1 we will get an even no. but z being prime cannot be even therefore x = 2 , y = 2, z = 5, also we take y = 2 because for other values of y(i.e y =3,5,7etc.), z will become divisible by 3.

Hope you understood

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