hey ..............sorry................but...........as it is a binomial theorem question.................. but i m doing it by different method...........
thanku...............
look.........
2=2 (mod 7) (means when 2 / 7 leaves remainder 2)
25 = 32 (mod 7)
25 = 4 ( mod 7) ( 32 divided by 7 gives 4)
3232 = 4 32 (mod 7) ( raising power of 32 on both sides)
3232 = 264 (mod 7) .................... ( 1)
now lets find remainder obtained by 7 of 264
2 = 2 ( mod 7)
22 =4 (mod 7)
24 = 2 ( mod 7) (as 16 divided by 7 gives remainder 2)
28 = 22 =4 (mod 7)
216 = 2 ( mod 7) ( as 16 divided by 7 gives 2 rem)
232 = 4 ( mod 7)................................. ( 2 )
2 64 = 2 ( mod 7) ( as 16 gives 2 rem)..............( 3)
putting (3) in (1)............... we get ............
3232= 2 ( mod 7 )
323232 = 232
now putting 2 in 1...............
we get
323232= 4 ( mod 7)..........................
ya.. ya i know it its sometime confusing...................but............i have tried my best to explain it hope u understands...........
thanku.............