NOW 4 SECOND..........

 

(2222)= 3  (MOD 7)

(2222)³ = 27  (mod 7)

(2222)³= -1   (mod7)

(2222)⁵⁵⁵³=  -1  ( mod 7) ..(1)         ( as 5555 not divisible by 3 only 5553

                                                        is divisible by 3)

2222=3 (mod 7)

2222²= 9 (mod 7)

2222² =2( mod7)  .....( 2)

 

multiplying 1 & 2............we get.......................

 

(2222)⁵⁵⁵⁵ =  -2  (mod 7)

                 = 5   (remainder)

 

i hope i m right .............

pls      

 

check the answer...........

 

thanku