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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2008 14:58:17 IST
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SUPPOSE AT TIME T THE PARTICLE BREAKS
SO THE VERTICAL COMPONENT OF VELOCITY WILL BE
ut-1/2at^2
THE HORIZONTAL COMPONENT OF VELOCITY WILL BE
vt
S RESULTANT VEOCITY WILL BE
UNDER ROOT(ut-1/2at^2)^2+(vt)^2
ACCPRDING TO LAW OF CONSERVATION OF MOMENTUM
MV(RESULTANT)=(M-m)v1 mv2
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