angle of incidence = angle b/w -2i + 3j - 4k & 3i - 6j + 2k
= cos
-1 (-32/7
29) by dot product...
let r be the unit vector along the reflected ray..
so angle of reflection = angle b/w r and 3i - 6j + 2k
= cos-1(r.(3i - 6j + 2k) / 7)
since angle of incidence = angle of ref
-32/
29 = r.(3i - 6j + 2k)
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Moderation Team
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