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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2008 16:57:14 IST
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[760- 740]/760= mole fraction of glucose
Suppose we have 1 mole of water
den
20/760 = x/x+1
Solvin we get x = 20/740
whr x = number of moles of glucose
now
elevation in BP = Kb * molality
= [Kb* 20 * 1000]/ 18* 740
So new BP = 100+ abv expression
i hope its clear
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I Tried So Hard And Got So Far
But In The End
It Doesnt Even Matter... |
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