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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: no of solutions.........find plz.........
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little_genius (295)

Blazing goIITian

Olaaa!! Perrrfect answer. 53  [68 rates]

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let me give the solution for any given no ....it wud be helpful....

let n= x1x2x3.x4x5= 2^a,3^b,5^c.....

then x1 = 2^@1.3^@2.5^@3.........
similarly for x2,x3,x4....

now we have @1 +%1 +.....= a total no of integral soln will give the answer........

this is a very long method but i tried it myself ...others may give shorter ways....


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