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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Apr 2008 11:37:19 IST
Accepted Answer [?]
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No I think its a hyperbola
x + i y = z = 1 - t + i  (t2 + t + 1)
So
we have to eliminate t
x = 1 - t
Hence t = 1 - x
y = (t2 + t +1)
y 2 = t2 + t + 1
or y 2 = (1 - x) 2 + 1- x + 2 = 1 - 2x + x2 + 3 - x = x2 + 4 - 3x
or y2 = (x - 3/2 ) 2 + 7/4
So y2 - (x - 3/2) 2 = 7/4
which represents a hyperbola .
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this reply: 10 points
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in 2 votes ) [?]
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