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Discussion Response Post to: hyperbola question

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Bipin Dubey (13679)

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Shift the origin such that the new co-ordinates would be (X,Y) = (x-c,y-c)
i.e. x = X + c and y = Y + c

1/x + 1/y = 1/c
c(x+y) = xy

c(X + c + Y + c) = (X + c)(Y + c)
cX + cY + 2c² = XY + cX + cY + c²
XY = c²

I think rest of the part you can do on your own.

Bipin Kumar Dubey Chemical Dept. IIT Kharagpur

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