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[Post New]22 Apr 2008 21:54:51 IST
    Subject: Re:maximum value...
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anchitsaini (4332)

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Consider --\\ \\ \frac{x}{2} , \frac{x}{2}, \frac{y}{3} , \frac{y}{3}, \frac{y}{3} , z \\ \\ AM=\frac{\frac{x}{2} + \frac{x}{2} + \frac{y}{3} + \frac{y}{3} + \frac{y}{3} + z}{6} \\ \\ =\frac{x+y+z}{6} = 2 \\ \\ GM = (\frac{x^2y^3z}{108})^{1/6} \\ \\ Using \ AM \geq GM \\ \\ MAX \ value \ of \ \\ \\ x^2y^3z=2^6*108 \\ \\ =6912
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