IIT JEE , AIEEE Forum - Physics , Mechanics - QUE IN MECH... PLZ HELP ME OUT..RATES ASSURED..

varun.tinkle

SEE AT THE TOPMOST POINT OF THE CIRCLE
THE EQUATION IS
MG +T=MV^2/L

AND A THE LOWERMOST POINT IS
T-MG=MV^2/L

OBVIOUSLY THE MAX TENSION IS AT THE LOWEST POINT WHICH IS EQUAL TO MG+MV^2/L
AND THE MIN TENSION IS AT THE HIGHEST POINT
WHICH IS EQUAL TO MV^2/L-MG
EQUATE THE EQUATIONS
AND FIND THE VARIABLES
THE SPPED AT THE TOPMOST POINT WILL BE FORMULATED BY THE EQUATION
MG +T=MV^2/L
REMEMBER THE RADIUS WILL BE L/2
WHERE L IS THE LENGTH OF THE SPRING
PLZ RATE ME IF U FIND ME USEFUL
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