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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Apr 2008 18:57:48 IST
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method 1...
take this as y = 2^sinx + 2^cosx...
just differentiate..
dy/dx = cosx.2^sinxlog2 - sinx.2^cosx.log2..
this method wasn't good ..
2^sinx,cosx both r positive...
lets use inequalities..
a-m - gm..
min. value is 2 root { 2^ (sinx + cosx)...}
sinx+ cosx at max. gives u. root2...
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Diamonds r formed under greatest pressures..
so r the champs.
Kriteesh..
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this reply: 5 points
(with 1 
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Moderation Team
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