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Since the two pith balls have equal and similar charge they mak equal angles a with the vertical.
Let the midpoint of the distance of separation between them be O, the pt of suspension be P and one of the charge q be at point Q.
For equilibrium,
F=Tsina
mg=Tcosa
F/mg= tana.......1
tana = OQ/OP
Put this value in 1 and get F
Now put the value of F in coulomb's equation and get q.
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Moderation Team
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