q) In how many ways can 10 different toys be distributed among 10 children so that exactly 2 of them get no toys.

my soln...

ways of selecting 2 children = 10C2

now all others should have atleast one...so 10C8*8! ways..

now the remaining 2 toys can be distributed in 8^2 ways..

so my ans is 10C2 * 10C2*8! * 8^2..

but this is not the right answer..plz point out the mistake in my answer and post the correct solution ..