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[Post New]29 Apr 2008 17:03:42 IST
    Subject: Re:solve it if u can!
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harsha_27 (1348)

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Olaaa!! Perrrfect answer. 226  [335 rates]
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Gravity at that point = Gravity due to the complete Asteroid(spherical) at that point - Gravity due to the removed part at that point.


so \ g_{net} = \frac{GM}{R^2} - \frac{G(\frac{M}{8})}{(\frac{R}{2})^2} \ (Mass \ of \ removed \ part \ = \frac{M}{8})\\ \\<br/>=> g_{net} = \frac{GM}{2R^2}


 


 


 
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