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Q 1 m = 1 as u can see curve passes through P ( b, 1 ) also slope of the curve = - my/ x slope at P = -m/b the equation of tangent at P = (y - 1) / ( x - b) = -m /b
this line meets x and y axis at ( b( 1 + m)/ m , 0 ) and ( 0 , 1 + m )
area of triangle = 1/2 b ( 1 + m )^2 / m
to get m differentiate it and put equal to 0 as it is constant
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