IIT JEE , AIEEE Forum - Mathematics , Analytical Geometry - challenge -- goood question

celestine

Nuksi
The ans which u gave is definitely wrong bcos it eventually bcoms the eq of 2 imaginary lines

Yes it is a combination of rot and shift of axes

eq is 2X^2 - 3Y^2 = 1
Formula for rot of axes is
X= (xcosO - ysinO)
Y= (xsinO + ycosO)
If eq of line is sometin else apply the shift in axes as X+ h and Y +k

h = -3 k = -2 ( lines intersect at 2,3 )

tanO = -1/2 ( slope of transverse)
sinO = -1/rt5 cosO = 2/rt5 ( O in 4th quad)

substitute and get

2 ( 2X + Y - 3)^2 - 3( 2Y - X - 2)^2 = 5

good question

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