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Discussion Response Post to: probability

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4 May 2008 13:28:27 IST

Subject: Re:probability

sandeepramesh (1247)

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We have to consider the number of pairs of 2 consecutive letters. By baye's theorem

P = $\frac{\frac{1}{4}}{\frac{1}{4}+\frac{1}{8}+\frac{1}{7}+\frac{1}{5}} = \frac{8*7*5}{(8*7*5)+(4*7*5)+(4*8*5)+(4*8*7)} =$ $\frac{240}{804}$

Have i made any mistake?

this reply: 5 points (with 1 Olaaa!! Perrrfect answer.

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