IIT JEE , AIEEE Forum - Mathematics , Algebra

Discussion Response Post to: logarithms

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4 May 2008 18:38:46 IST

Subject: Re:logarithms

hsbhatt (4460)

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Not quite sure what you need because it can be shown that

$\frac{a^a+b^b+c^c}{3} \ge \sqrt [3] {a^a b^b c^c} \ge (abc)^{\frac{a+b+c}{9}}$

If you could supply the choices, maybe we could manoeuver further!!

Time wounds all heels

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