x^3-1=0  is factor

thn  x-1   and  x^2+x+1  are factors

when we substitute 1 in equation we get  a+b+c=-6_____________1

and dividing given equation with x^2+x+1  we get remainder as

x(a-c+2) + (b-c+1)

but remainder shuld be zero   therefore  a-c+2=0_______2   and  b-c+1=0_________3

* x cannot be zero bcoz if x is zero and if we substitute 0 in equation we get

2=0  which is absurd

by solving 1,2,3 equations we get   a=-3   b=-2   c=-1therefore answer is -36