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I can't give you the answer, but I can tell you what to do... I don't exactly know those star deltas or whatever........ Just one method would help you solve any problem..... I use just this one....
assume a charge Q1 on one of the left most plates....say on 5uF capacitor..... and charge on 15uF capacitor , on the left plate, is Q2
charges on the right plates of the 5 uF , 15 uF are then -Q1, -Q2
The positive charge, negative charge supplied by the batteries is the same in magnitude, so the net charge on the right plates of 10uF, 20uF must be equal to -(Q1+Q2)
assume some charges on them.....
now, the charge on top plate of 25uF is -(charge on right plate of 5uF+ charge on left plate of 10uF) and similarly charge on the bottom plate.....
you are left with 4 variables... charges on four outer capacitors.... one equation is obtd from the fact that charge supplied by positive terminal of batt= that by negative terminal in magnitude......
You get 3 more equations from the 3 loops in the connections, you solve them to get the answer
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Moderation Team
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