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![[Post New]](/templates/default/images/icon_minipost_new.gif) 7 May 2008 22:49:00 IST
Accepted Answer [?]
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vertex is mid pt of focus n directrix
meeting pt of drtx =(m,n)
1=(m-2)/2
m=4
similarly
n=1
slope if axis =-1/3
thus slope of drtx=3(perpendicular to axis )
now
eqn to drtx=3=(y-1)/(x-4)
frm dis eqn den put
distanc frm dirtx=distance frm focus
(3x-y-11)^2/10=(x+2)^2(y-3)^2
hence d eqn
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even a stopped clock is right twice a day |
this reply: 5 points
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