dekh yaara.......not that my answer is wrong.........but that its the shorter method of doin the same thing.......taking the pressure at an element of width dh ............finding the force at that pt and integrating the vertical component of that force from h=0 till h=H toh koyi bhi kar sakta hai........thats the technical soln. as posted very rightly by learner..........a much much simpler short cut will be to do it using the force balancing........net force on the water=0..............so the force due to the wt= normal force given by the ground + force given by the curved wall in the upward direction........normal force by bottom of beaker= Pressure exerted by the water* area of bottom............and wt of the liquid can be gotten by using M=V*d..............now for getting V ull have to do some additional work which i havnt done and left for u to do........REMEMBER i havnt posted the full soln. ........ive jus given a methodology to do the problem.....i cant attach paint files (due to technical probs. on my comp)other wise i wud hav posted a much detailed soln.........u have any debates to make abt this soln.....ur open to come on my nudgebook and i can prove my pt thru arguement............thnku........