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aditi_g (355)

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Olaaa!! Perrrfect answer. 57  [92 rates]

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2) ie . Q20

ist put x=0 u get y= ae^pi/2

take log on both sides



write it as 1/2 log(x^2+y^2)


now differentiate and simplify


ull get x+y dy/dx = x dy/dx - y


x+y= (x-y)dy/dx ..............1)


put x=0 dy/dx = -1


now differentiate eqn 1) again


1+dy/dx = (1-dy/dx)dy/dx + (x-y) d^2y/dx^2


put x=0,also whn x=0 dy/dx=-1 and y= a e^pi/2


put all the values ull get d^2/dx^2 = -2/a(e ^ -pi/2)


i hope its clear


 


 

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