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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Pls ans What are the last two digits of no "9^200"??Plz explain in detail...
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aditi_g (355)

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Olaaa!! Perrrfect answer. 57  [92 rates]

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write it as (10-1)^200
whn u expand ull get
200 C 0 - 200 C 1 10 + 200C2 100 - 200.............200C200 10^200
now c the first term is 1 second is -2000 third wud be even greater ie.1990000.. and so on.....
now apart frm the first term no other number will have any digit in the ones and tens place...in all other terms it wud be 0 and so wud not contribute...
so the last 2 digits wud be 01..
i hope its clear
lemme knw if u still have any doubt
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