IIT JEE , AIEEE Forum - Mathematics , Algebra - Pls ans What are the last two digits of no "9^200"??Plz explain in detail...

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11 May 2008 10:49:34 IST

Subject: Re:Pls ans What are the last two digits of no "9^200"??Plz explain in detail...

pantpranav (387)

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There's another method : The method of observation.

9¹ = 09

9² = 81

9³ = 729

9⁴ = 6561

9⁵ = 59049

9⁶ = 531441

Hence, it is observed that every even power ends in 1.

The digit in ten's place is 8, then 6, then 4 & so on.

So, for 9²⁰⁰ , it should be 0.

Hence the answer is 01.

this reply: 10 points (with 2 Olaaa!! Perrrfect answer.

in 2 votes ) [?]

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