2nd ques

from where u get such ques man?

Tell me if I m going inthe right dir.

As I see p(x²)=(p(x))² is possible only when x=0 and equating we get

a₀ =a₀²  which gives a₀=0 or a₀=1.

it is also possible when x=1and on equating we get

(a₀+a₁+.......+a_n)=(a₀+......+a_n)²

which again gives  (a₀+ .......+a_n)=0 or (a₀+.........+a_n)=1.