IIT JEE , AIEEE Forum - Mathematics , Algebra - binomial theorem . generic approach for solving these types of problems

Greatdreams

$Good \;work ; however\;it\;can\; be\;written \;as\;:$

$5^{99} = 5^{3}.5^{96} = 125 . (625)^{24}$

$= [13.9 +8](1 + 48.13)^{24}$

$Now \;expand\;binomially\;;$

$Hence \; it\;is=(13.9+8)[1+^{24}C_{1}.48.13 + ^{24}C_2(48.13)^{2}+..................]$

$Hence\; 8\;is\;remainder\;!$

$w.r.t \;the\;previous\;post ;$

$a \;=\;b(mod)c \rightarrow when\;a\;is\;divided\;by\;c\;;b\;is\;the\;remainder$

$P.S-36\;seconds\;differnce\;between\;rabiit\;and\;me.$

$Answer \;has\; been\;edited\;a\;bit!$