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Discussion Response Post to: Challenge in Integration - From Feynmann

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11 May 2008 13:04:02 IST

Subject: Challenge in Integration - From Feynmann

feynmann (2189)

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Solve the following in the shortest possible way

$If\;a>b>0,\;show\;that$ $\int_{0}^{\pi}({sin}^{2}x)/({a}^{2}\;+{b}^{2}-2ab\;cosx) \;dx\;=\frac{\pi}{2{a}^{2}}$

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