n]
[ 
] 1/n[(1+n)(2+n)..............(n+n)]
1/n Let the limit be =I
I= [(1/n+1)(2/n+1)........................(n/n +1)]1/n
take log of both sides
now
log I=1/n (
[r=1 ]
[r=infinity ] log(r/n+1))
now this is limit of sum
logI=
[ 0]
[ 1] log(x+1).dx
log I=log(4/e)
answer is 4/e
is my answer correct
dont i look like an idiot
Moderation Team
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