FOR EQULIBRIUM THE VERTICAL AND HORIZONTAL FORCES SHOULD BE EQUAL

THEREFORE  

N1=F 

N2=W

TAKING THE TORQUE OF THE FORCES ABT POJNT B ( U CAN CHOOSE ANY POINT BUT ACCORDING TO ME ITS MORE CONVINIENT)

N1(AO)=W(CB)

N1 AB COS53=WAB/2 SIN 53

N13/5=W/2*4/5

N1=2/3 W

WEIGHT =N1=10(9.8)=98N

N1=f=98/2/3=65N

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