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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Non conducting sphere and sherical shell problem.
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pink_ele (1156)

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Olaaa!! Perrrfect answer. 190  [293 rates]

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now for part c )
at a dis tance of 2a +r
net charge=Q-Q/(vol of shell))x(vol of shell formed within req distance)
=Q-(Q/19a^3) x(r^3-8a^3)
=Q(11a^3-r^3)
therefore
Ex 4 pi (2a+r)^2=Q(11a^3-r^3)/e not
E=Q(11a^3-r^3)/4 pi (2a+r)^2 e not

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