Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: isobaric process
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Bipin Dubey (13679)

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Change in internal energy would be

nCV(T2 - T1)  =  nCV(PV2/nR - PV1/nR)
                 
                   =  (PCV/R)(2V - V)
              
                   =  PV/(-1)

It depends on initial and final states, hence there is no need of process to be known.

Bipin Kumar Dubey Chemical Dept. IIT Kharagpur
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