IIT JEE , AIEEE Forum - Mathematics , Algebra

refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team

Ask iit jee aieee pet cbse icse state board community

Discussion Response Post to: no. of .....

Forum Index -> Algebra -> View Full Question

Author

Message

15 May 2008 01:05:43 IST

Subject: Re:no. of .....

Greatdreams (3220)

Forum Expert Moderator

612 [692 rates]

total posts: 610
Offline

$There\;should\;be\;2\;ways:$

$a.)considering\;+ve\;numbers\;only$

$b.)considering\;-ve\;numbers\;also$

$So\;first\;case\;; \;$

$Hence;number\;of \;solutions = 3!+3!/2!.2+3!+3!+3! =5.3! = 30$

$Now\;considering\;-ve\;numbers\;also;2 \;numbers\;have\;to\;be\;negative\;to\;make\;product\;+ve$

$Hence;number\;of\;ways=30+30.^3C_2 = 120$

$Hence\;number\;of\;ways=120$

__________________________________________________________________________________________________________
From J.R.R. Tolkien's 'The Lord of the Rings':

All that is gold does not glitter
Not all who wander are lost
The old that is strong does not wither,
Deep roots are not reached by frost.
From ashes a fire shall be woken
From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.

this reply: 10 points (with 2 Olaaa!! Perrrfect answer.

in 2 votes ) [?]

You have to be logged on to rate

Top Offers for goIITians


Correspondence Courses
	Brilliant Tutorials
	Narayana Institute
	Aakash Institute

Classroom/Crash Courses
	Narayana - Kota , Delhi , Others
	Brilliant Tutorials - Class , Crash
	Aakash Institute - Medical , Engg

Online Test Series
	Brilliant Tutorials
	Narayana Institute
	Aakash Institute
	Mahesh Tutorials
	AMITY Sri Chaitanya