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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: field due to a conducting plate
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prateek2292 (136)

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Olaaa!! Perrrfect answer. 22  [35 rates]

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since it is a closed surface then we have to consider both the surfaces.
for a plane sheet E=Q/2epsilon.
But, for a conducting sheet u have to consider both the surfaces because it acts as a plate and plate have some thickness.
therefore,bcauz of both the surfaces..
E=Q/2epsilon+q/2epsilon
=Q/epsilon.





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