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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 18:21:51 IST
Accepted Answer [?]
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Let The point below P in plane of eyes of prisioner at A and B is Q
Let PQ=h
and
AQ=b
From first
tan(31)=h/b
By pythagorus theorm
BQ=sqrt(b^2+15^2)
Therefore
tan(25)=h/sqrt(b^2+15^2)
Using the two equations solve for h and b.
Height of point P=h+1.7 meters
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
this reply: 5 points
(with 1 
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