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 Discussion Response Post to:
solve
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| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 May 2008 20:36:27 IST
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%20%2B%20(cotx)}%20=%20sinx%2Bcosx/\sqrt{sinx%20cosx})
/\sqrt{sin%202x})
/%20\sqrt{1-(1-%20sin2x)})
/\sqrt{1-(sinx%20-%20cosx)^2})
%20%2Bc%20;%20you%20\;can%20\;simplify%20\;further%20.)
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From J.R.R. Tolkien's 'The Lord of the Rings':
All that is gold does not glitter
Not all who wander are lost
The old that is strong does not wither,
Deep roots are not reached by frost.
From ashes a fire shall be woken
From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king. |
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