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Discussion Response Post to: Dilute soltions and colligative properties

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Priyesh (1601)

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mole fraction of benzene in liquid is (80/78)/(80/78 + 100/92)

so total vapour pressure = 50.71 * (mole fraction of benzene) + 32.06*(1-mole fraction of benzene)

now by dalton's law mole fraction of benzene in vapour state = partial pressure of benzene /total pressure

= [50.71 * (mole fraction of benzene)]/total vapour pressure

do the calculations & put the values to get the ans

"Imagination is more important than knowledge."

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