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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2008 19:56:59 IST
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U know the mass of ethane in each case and also the molar mass of ethane. SO u know the no. of moles of ethane in each case.
Now, mole fraction= moles of ethane/total no of moles
Let the moles of ethane=n, and moles of solvent=N.
As the mass of ethane taken is very less, we can assume n+N~N.
Now while calculating the ratio, this N will get cancelled and U will get ur answer.
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