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Discussion Response Post to: first derivative

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Priyesh (1601)

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limh $\rightarrow$ 0 f(x+h)-f(x)/h= limh $\rightarrow$ 0 [f(x) + f(h) - f(x)]/h (as it is given that f(x+y) = f(x) + f(y)

= limh $\rightarrow$ 0 f(h)/h now f(h) = h^2g(h) (bcoz it's given that f(x) = x^2g(x))

=> limh $\rightarrow$ 0 f(h)/h = limh $\rightarrow$ 0 hg(h) = 0

hope now u have understood

"Imagination is more important than knowledge."

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